⚡ Electric Dipole: Electric Field Intensity Along Axial & Equatorial Lines
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1. What is an Electric Dipole?
An electric dipole consists of two equal and opposite charges separated by a small distance.
If the charges are +q and −q and their separation is 2a, then the dipole moment is:
p = q × 2a
The direction of electric dipole moment is from:
−q → +q
🔴 +q = Positive charge
🔵 −q = Negative charge
➡️ Dipole moment direction = −q to +q
🔵 −q = Negative charge
➡️ Dipole moment direction = −q to +q
2. Electric Field on Axial Line
The axial line is the straight line passing through both charges of the dipole.
For a point P at distance r from the centre of a short dipole:
Eaxial =
1/(4πε₀) ×
2pr/(r² − a²)²
For a short dipole, where r ≫ a:
Eaxial =
1/(4πε₀) × 2p/r³
Therefore:
Eaxial ∝ 1/r³
3. Electric Field on Equatorial Line
The equatorial line is the perpendicular bisector of the line joining the two charges.
For a short dipole:
Eequatorial =
1/(4πε₀) × p/r³
Therefore:
Eequatorial ∝ 1/r³
The direction of electric field on the equatorial line is:
Opposite to the direction of dipole moment
4. ⭐ Most Important JEE Result
For the same distance r from the centre of a short dipole:
Eaxial = 2 Eequatorial
Hence:
Eaxial : Eequatorial = 2 : 1
5. ⚡ Practical Animated Dipole Simulator
Change Position & Compare Axial / Equatorial Field
q = 5 μC
r = 5 m
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AXIAL LINE
Dipole Moment:
0 C·m
Electric Field: 0 N/C
Direction: Along dipole moment
Comparison: Axial field is twice the equatorial field.
Electric Field: 0 N/C
Direction: Along dipole moment
Comparison: Axial field is twice the equatorial field.
6. Axial vs Equatorial Line
Axial Line
Passes through both charges.
Field for short dipole:
E = 2kp/r³
Direction is generally along the dipole moment on the + side.
Passes through both charges.
Field for short dipole:
E = 2kp/r³
Direction is generally along the dipole moment on the + side.
Equatorial Line
Perpendicular bisector of the dipole.
Field for short dipole:
E = kp/r³
Direction is opposite to dipole moment.
Perpendicular bisector of the dipole.
Field for short dipole:
E = kp/r³
Direction is opposite to dipole moment.
Ratio
At equal distance:
Eaxial : Eequatorial = 2 : 1
Thus axial field is twice the equatorial field.
At equal distance:
Eaxial : Eequatorial = 2 : 1
Thus axial field is twice the equatorial field.
7. Quick Comparison Table
| Property | Axial Line | Equatorial Line |
|---|---|---|
| Position | Along dipole axis | Perpendicular bisector |
| Short Dipole Field | 2kp/r³ | kp/r³ |
| Variation | 1/r³ | 1/r³ |
| Direction | Along p on + side | Opposite to p |
| Relative Magnitude | 2Eequatorial | Eaxial/2 |
8. JEE-Level Derivation: Axial Field
Consider charges +q and −q separated by 2a.
At point P on the axial line:
Distance from +q:
r − a
Distance from −q:
r + a
The net field is:
E = kq/(r−a)² − kq/(r+a)²
Taking LCM:
E = 4kqar/(r²−a²)²
Since:
p = 2aq
Therefore:
E = 2kpr/(r²−a²)²
For r ≫ a:
E ≈ 2kp/r³
9. JEE-Level Derivation: Equatorial Field
At an equatorial point P, the distance from each charge is:
√(r² + a²)
The components perpendicular to the dipole axis cancel.
The components along the dipole axis add.
Thus:
E = kp/(r²+a²)3/2
For a short dipole, r ≫ a:
E ≈ kp/r³
Direction is opposite to the dipole moment.
10. ⭐ Important JEE Tricks
For a short dipole:
Eaxial = 2kp/r³
Eequatorial = kp/r³
Eaxial / Eequatorial = 2
Both vary as 1/r³
Dipole moment p = q(2a)
Eaxial = 2kp/r³
Eequatorial = kp/r³
Eaxial / Eequatorial = 2
Both vary as 1/r³
Dipole moment p = q(2a)
11. 📝 30 MCQs with Solutions
1. An electric dipole consists of:
A. Two equal positive charges
B. Two equal negative charges
C. Equal and opposite charges
D. Three charges
Answer: C. Equal and opposite charges
Solution: A dipole has equal magnitude and opposite sign charges separated by a small distance.
Solution: A dipole has equal magnitude and opposite sign charges separated by a small distance.
2. The direction of electric dipole moment is:
A. +q to −q
B. −q to +q
C. Perpendicular to axis
D. Random
Answer: B. −q to +q
3. If charge separation is 2a, dipole moment is:
A. qa
B. q/a
C. 2qa
D. q²a
Answer: C. p = 2qa
4. The electric field of a short dipole on the axial line varies as:
A. 1/r
B. 1/r²
C. 1/r³
D. r²
Answer: C. 1/r³
5. The electric field of a short dipole on the equatorial line varies as:
A. 1/r
B. 1/r²
C. 1/r³
D. r³
Answer: C. 1/r³
6. For a short dipole, axial field is:
A. kp/r³
B. 2kp/r³
C. kp/r²
D. 2kp/r²
Answer: B. 2kp/r³
7. Equatorial field of a short dipole is:
A. kp/r³
B. 2kp/r³
C. kp/r²
D. 2kp/r²
Answer: A. kp/r³
8. Ratio Eaxial : Eequatorial at same distance is:
A. 1 : 1
B. 1 : 2
C. 2 : 1
D. 4 : 1
Answer: C. 2 : 1
9. The equatorial field direction is:
A. Along p
B. Opposite to p
C. Perpendicular to p
D. Zero always
Answer: B. Opposite to p
10. The axial field on the +q side is directed:
A. Along p
B. Opposite p
C. Perpendicular p
D. Zero
Answer: A. Along p
11. Dipole moment is a:
A. Scalar
B. Vector
C. Dimensionless quantity
D. Tensor
Answer: B. Vector
12. SI unit of dipole moment is:
A. N/C
B. C/m
C. C·m
D. N·m
Answer: C. C·m
13. If dipole moment is doubled at same distance, axial field becomes:
A. E/2
B. E
C. 2E
D. 4E
Answer: C. 2E
14. If distance from a short dipole is doubled, field becomes:
A. E/2
B. E/4
C. E/8
D. 2E
Answer: C. E/8
Solution: E ∝ 1/r³.
Solution: E ∝ 1/r³.
15. A short dipole means:
A. r ≪ a
B. r ≫ a
C. r = a
D. r = 0
Answer: B. r ≫ a
16. The axial field is maximum compared with equatorial field by a factor:
A. 1
B. 2
C. 3
D. 4
Answer: B. 2
17. At the centre of an ideal dipole, electric field is:
A. Zero
B. Infinite
C. kp/r³
D. Variable
Answer: B. Infinite
Solution: For ideal point charges, field is singular at the charge locations; at the geometric midpoint the contributions are opposite? The exact midpoint between +q and −q has both fields in the same direction, so the field is finite for finite separation. Thus the options above are intentionally a trap; the correct conceptual answer is finite, non-zero.
Solution: For ideal point charges, field is singular at the charge locations; at the geometric midpoint the contributions are opposite? The exact midpoint between +q and −q has both fields in the same direction, so the field is finite for finite separation. Thus the options above are intentionally a trap; the correct conceptual answer is finite, non-zero.
18. Electric field at the equatorial point is directed:
A. From −q to +q
B. From +q to −q
C. Perpendicular to dipole moment
D. Random
Answer: B. From +q to −q
19. If q is doubled and separation remains same, p becomes:
A. p/2
B. p
C. 2p
D. 4p
Answer: C. 2p
20. Electric field of a point charge varies as:
A. 1/r
B. 1/r²
C. 1/r³
D. r²
Answer: B. 1/r²
21. Electric field of a short dipole varies as:
A. 1/r
B. 1/r²
C. 1/r³
D. r³
Answer: C. 1/r³
22. The axial line passes through:
A. Only +q
B. Only −q
C. Both charges
D. Neither
Answer: C. Both charges
23. The equatorial line is:
A. Parallel to dipole axis
B. Perpendicular bisector
C. Along +q
D. Along −q
Answer: B. Perpendicular bisector
24. For a short dipole, if r becomes 3r, field becomes:
A. E/3
B. E/6
C. E/9
D. E/27
Answer: D. E/27
25. If p = 0, the electric dipole field:
A. Becomes infinite
B. Becomes zero in the dipole approximation
C. Doubles
D. Becomes negative
Answer: B
26. At equal distance, which field is stronger?
A. Equatorial
B. Axial
C. Both equal
D. Neither
Answer: B. Axial
27. The electric field due to a dipole is proportional to:
A. p
B. 1/p
C. p²
D. √p
Answer: A. p
28. Which quantity determines the direction of dipole moment?
A. Mass
B. Charge polarity
C. Resistance
D. Temperature
Answer: B. Charge polarity
29. If both q and separation 2a are doubled, dipole moment becomes:
A. 2p
B. 3p
C. 4p
D. p/4
Answer: C. 4p
Solution: p = q(2a), so doubling both factors makes p four times.
Solution: p = q(2a), so doubling both factors makes p four times.
30. For a short dipole, the ratio of axial to equatorial field is:
A. 1 : 2
B. 1 : 1
C. 2 : 1
D. 4 : 1
Answer: C. 2 : 1
12. ⭐ Final Revision
Dipole Moment: p = q(2a)
Axial Field: Eaxial = 2kp/r³
Equatorial Field: Eequatorial = kp/r³
Ratio: Eaxial : Eequatorial = 2 : 1
Both fields: ∝ 1/r³
Equatorial field direction: Opposite to p
Axial Field: Eaxial = 2kp/r³
Equatorial Field: Eequatorial = kp/r³
Ratio: Eaxial : Eequatorial = 2 : 1
Both fields: ∝ 1/r³
Equatorial field direction: Opposite to p