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CBSE Class 10 Mathematics Standard (041) Sample Paper 8 - 2026-27

CBSE Class 10 Mathematics Standard (041) Sample Paper 8 - 2026-27
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CBSE Sample Practice Paper — 8  (Session 2026–27)
Class: X (10th)
Subject: Mathematics (Standard) — Code: 041
Time: 3 Hours
Max. Marks: 80
Student Name: ______________________ Roll No.: __________ Section: __________

General Instructions:

1. This Question Paper has 5 Sections A, B, C, D and E.

2. Section A comprises 20 MCQs (including 2 Assertion-Reason questions) of 1 mark each.

3. Section B comprises 5 Very Short Answer (VSA) questions of 2 marks each.

4. Section C comprises 6 Short Answer (SA) questions of 3 marks each.

5. Section D comprises 4 Long Answer (LA) questions of 5 marks each.

6. Section E comprises 3 Case-Study based questions of 4 marks each, with sub-parts of 1, 1 and 2 marks.

7. All questions are compulsory. Internal choices have been provided in 2 questions of Section B, 3 questions of Section C, 2 questions of Section D, and in one sub-part of each Case-Study question of Section E.

8. Draw neat figures wherever required. Take π = 22/7 wherever not stated otherwise.

9. Use of calculators is not permitted.

SECTION A  (1 Mark each) — Q1 to Q20
Q1. The exponent of 5 in the prime factorisation of 3750 is: 1
(A) 2(B) 3(C) 4(D) 5
Q2. The number 0.6875 can be expressed in the form p/q as: 1
(A) 11/16(B) 13/16(C) 7/16(D) 9/16
Q3. If n = 2³ × 3⁴ × 5 × 7, the number of consecutive zeros at the end of n is: 1
(A) 0(B) 1(C) 2(D) 3
Q4. If the zeroes of the polynomial x³ − 3x² + x + 1 are a−b, a, a+b, find a. 1
(A) 1(B) −1(C) 3(D) 0
Q5. The pair of equations x = a and y = b graphically represents lines which are: 1
(A) parallel to each other(B) coincident(C) intersecting at (a, b)(D) intersecting at (b, a)
Q6. If one root of the quadratic equation 2x² + kx − 6 = 0 is 2, the value of k is: 1
(A) −1(B) 1(C) −6(D) 6
Q7. The sum of the first n odd natural numbers is: 1
(A) n(B) n²(C) n(n+1)(D) n(n+1)/2
Q8. Two numbers are in the ratio 3 : 4 and their LCM is 84. The HCF of the numbers is: 1
(A) 7(B) 12(C) 21(D) 28
Q9. In ΔABC, DE ∥ BC and AD : DB = 1 : 2. Then ar(ΔADE) : ar(ΔABC) is: 1
(A) 1 : 2(B) 1 : 3(C) 1 : 9(D) 1 : 4
Q10. If in ΔABC and ΔDEF, ∠A = ∠D and ∠B = ∠E, then the triangles are similar by: 1
(A) SSS(B) SAS(C) AA(D) RHS
Q11. A circle can have at most how many parallel tangents? 1
(A) 1(B) 2(C) 3(D) infinite
Q12. If cosecθ − cotθ = 1/3, then cosecθ + cotθ equals: 1
(A) 1/3(B) 3(C) 1(D) 9
Q13. The angle of elevation of the sun, when the length of the shadow of a pole equals the height of the pole, is: 1
(A) 30°(B) 45°(C) 60°(D) 90°
Q14. If the radius of a circle is doubled, its area becomes: 1
(A) double(B) triple(C) 4 times(D) the same
Q15. A number is selected at random from 1 to 100. The probability that it is a perfect square is: 1
(A) 1/10(B) 1/5(C) 9/100(D) 11/100
Q16. The mean of 5 observations x, x+2, x+4, x+6, x+8 is 15. Find x. 1
(A) 11(B) 9(C) 13(D) 7
Q17. If the nth term of an AP is (2n+1), the sum of its first n terms is: 1
(A) n² + 2n(B) n² + n(C) 2n² + n(D) n²
Q18. The product of the zeroes of the polynomial 4x² − 9 is: 1
(A) −9/4(B) 9/4(C) −4/9(D) 4/9
Q19. Assertion (A): The lengths of tangents drawn from an external point to a circle are equal.
Reason (R): The perpendicular from the centre of a circle to a chord bisects the chord. 1
(A) Both A and R are true, and R is the correct explanation of A. (B) Both A and R are true, but R is NOT the correct explanation of A. (C) A is true, but R is false. (D) A is false, but R is true.
Q20. Assertion (A): If cosA = 0, then sinA = 1.
Reason (R): sin²A + cos²A = 1 for all values of A. 1
(A) Both A and R are true, and R is the correct explanation of A. (B) Both A and R are true, but R is NOT the correct explanation of A. (C) A is true, but R is false. (D) A is false, but R is true.
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SECTION B  (2 Marks each) — Q21 to Q25
Q21. Show that 12ⁿ cannot end with the digit 0 for any natural number n. 2
Q22. Find the coordinates of point A, where AB is a diameter of a circle with centre (2, −3) and B is (1, 4). 2
— OR —
If (1, 2), (4, y), (x, 6) and (3, 5) are the vertices of a parallelogram taken in order, find x and y. 2
Q23. If sinθ = 1/2, find the value of 3cosθ − 4cos³θ. 2
Q24. Evaluate: sin60°cos30° + cos60°sin30°. 2
— OR —
If secθ = 13/12, find the value of (sinθ − 2cosθ)/(3sinθ − cosθ). 2
Q25. A box of 600 electric bulbs contains 12 defective bulbs. One bulb is taken out at random. Find the probability that it is (i) defective, and (ii) not defective. 2
SECTION C  (3 Marks each) — Q26 to Q31
Q26. A fraction becomes 4/5 if 1 is added to both its numerator and denominator. If 5 is subtracted from both, it becomes 1/2. Find the fraction. 3
Q27. Solve for x: √(x/(x−3)) + √((x−3)/x) = 5/2, where x ≠ 0, 3. 3
— OR —
Find the value of k for which the quadratic equation kx² + 2x + 1 = 0 has two equal real roots. 3
Q28. If the 8th term of an AP is 31, and the 15th term is 16 more than the 11th term, find the AP. 3
Q29. Two triangles ABC and DBC lie on the same base BC. If AD intersects BC at O, prove that ar(ΔABC)/ar(ΔDBC) = AO/DO. 3
Q30. Prove that the parallelogram circumscribing a circle is a rhombus. 3
— OR —
PA and PB are tangents from an external point P to a circle with centre O. If ∠PAB = 50°, find ∠AOB. 3
Q31. Calculate the median for the following distribution:
Class0–1010–2020–3030–4040–50
Frequency515202317
3
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SECTION D  (5 Marks each) — Q32 to Q35
Q32. A peacock is sitting on top of a pillar 9 m high. From a point 27 m away from the base of the pillar, a snake is coming towards its hole at the base of the pillar. Seeing the snake, the peacock pounces on it in a straight line. If their speeds are equal, find the distance from the hole where the snake is caught. 5
— OR —
The denominator of a fraction is one more than twice its numerator. If the sum of the fraction and its reciprocal is 2 1/16, find the fraction. 5
Q33. State and prove the converse of the Pythagoras Theorem: In a triangle, if the square of one side is equal to the sum of the squares of the other two sides, then the angle opposite the first side is a right angle. 5
Q34. A statue 1.6 m tall stands on top of a pedestal. From a point on the ground, the angle of elevation of the top of the statue is 60°, and from the same point, the angle of elevation of the top of the pedestal is 45°. Find the height of the pedestal. 5
Q35. From a solid cylinder of height 20 cm and diameter 12 cm, a conical cavity of the same height and same diameter is hollowed out. Find the total surface area of the remaining solid. (Use π = 22/7, and √436 ≈ 20.88) 5
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SECTION E — Case Study Based Questions  (4 Marks each) — Q36 to Q38
Q36. Case Study — Coordinate Geometry. An architect is designing a triangular garden plot with corners at A(1, 1), B(5, 1) and C(3, 4) on a blueprint grid (1 unit = 1 m).4
(i) Find the length of AB. (1)
(ii) Find the length of AC. (1)
(iii) The architect wants to place a fountain at the centroid of triangle ABC. Find its coordinates. (2)
[OR for (iii): Find the coordinates of the midpoint of BC, and hence describe how the fountain's position (centroid) relates to this midpoint and vertex A.]
Q37. Case Study — Mensuration. A company manufactures a solid toy in the shape of a hemisphere surmounted by a cone. The base radius of the cone is 3.5 cm and its height is 5 cm; the hemisphere has the same radius.4
(i) Find the slant height of the cone. (1)
(ii) Find the volume of the toy (cone + hemisphere). (1)
(iii) Find the total surface area of the toy. (2)
[OR for (iii): Find how much more volume the hemisphere contributes to the toy compared to the cone.]
Q38. Case Study — Probability. In a lottery, there are 10 prizes and 25 blanks. A lottery ticket is drawn at random from all the tickets.4
(i) Find the probability of getting a prize. (1)
(ii) Find the probability of not getting a prize. (1)
(iii) If two tickets are drawn one after another, without replacement, find the probability that both are prize-winning tickets. (2)
[OR for (iii): Find the probability that the first ticket is a prize and the second is a blank.]
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Design of Question Paper — Blueprint & Analysis
1. Blueprint — Section-wise Design
SectionQuestion TypeNo. of QuestionsMarks per QuestionTotal Marks
AMCQ (incl. 2 Assertion–Reason)20120
BVery Short Answer (VSA)5210
CShort Answer (SA)6318
DLong Answer (LA)4520
ECase Study Based (1+1+2)3412
Total80
2. Chapter-wise / Unit-wise Marks Distribution
Unit / Chapter GroupSec ASec BSec CSec DSec ETotal
Number Systems420006
Algebra (Polynomials, Linear Eq., Quadratic Eq., AP)6095020
Coordinate Geometry020046
Geometry (Triangles, Circles)4065015
Trigonometry3405012
Mensuration1005410
Statistics & Probability2230411
Total201018201280
3. Difficulty Level Analysis (Bloom's Taxonomy)
Cognitive LevelDescriptionMarksPercentage
Remembering & UnderstandingRecall of facts, definitions, direct formula-based questions4354%
ApplyingApplication of concepts to solve standard/routine problems1924%
Analysing, Evaluating & Creating (HOTS)Multi-step reasoning, proof-based, case-study and real-life application questions1822%
Total80100%
4. Learning Outcome (LO) Mapping
UnitKey Learning Outcomes Assessed
Number SystemsApplies Euclid's Division Lemma; identifies rational/irrational numbers; determines nature of decimal expansions.
AlgebraFinds zeroes and relationships of polynomials; solves pairs of linear equations by multiple methods; solves quadratic equations; applies AP formulae to real-life contexts.
Coordinate GeometryApplies distance and section formulae; determines area of a triangle using coordinates; interprets geometric figures on a coordinate plane.
GeometryProves and applies theorems on similar triangles, Pythagoras theorem, and tangents to a circle.
TrigonometryEvaluates trigonometric ratios and identities; applies trigonometry to height-and-distance real-life problems.
MensurationComputes areas of circles/sectors; finds surface areas and volumes of combined solids.
Statistics & ProbabilityComputes mean of grouped data; determines theoretical probability of simple and compound events.
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Complete Answer Key & Step-wise Marking Scheme
Section A — Answer Key (1 mark each)
QAnsQAnsQAnsQAns
1(C) 46(A) −111(B) 216(A) 11
2(A) 11/167(B) n²12(B) 317(A) n²+2n
3(B) 18(A) 713(B) 45°18(A) −9/4
4(A) 19(C) 1:914(C) 4 times19(B)
5(C) intersect at (a,b)10(C) AA15(A) 1/1020(A)
Section B — Key Answers (2 marks each)
Q21. Standard proof: 12ⁿ = 2^(2n) × 3ⁿ has no factor of 5, so it can never end in 0.
Q22. A = (3, −10). OR: x = 6, y = 3.
Q23. 3cosθ − 4cos³θ = 0 (using θ = 30°, this equals cos3θ = cos90° = 0).
Q24. sin60°cos30° + cos60°sin30° = sin90° = 1. OR: Value = −19/3.
Q25. P(defective) = 12/600 = 1/50; P(not defective) = 588/600 = 49/50.
Section C — Key Answers (3 marks each)
Q26. Fraction = 7/9.
Q27. x = 4 or x = −1. OR: k = 1 (for equal roots).
Q28. First term a = 3, common difference d = 4; AP: 3, 7, 11, 15, ...
Q29. Standard proof: triangles ABC and DBC have the same base BC, so the ratio of their areas equals the ratio of their heights from A and D, which in turn equals AO/DO (using similar triangles formed with the intersection point O).
Q30. Standard proof using tangent-length equality (AP=AS, BP=BQ, etc.) and the parallelogram property. OR: ∠AOB = 100°.
Q31. Median = 30 (median class 20–30, using the median formula for grouped data).
Section D — Key Answers (5 marks each)
Q32. Distance from the hole where the snake is caught = 12 m. OR: Fraction = 3/7.
Q33. Standard proof by contradiction, constructing a right triangle with the same two legs and showing it must be congruent to the original triangle (SSS), forcing the angle to be 90°.
Q34. Height of pedestal ≈ 2.19 m (using h = 1.6/(√3−1)).
Q35. Total surface area ≈ 1261.4 cm² (curved surface of cylinder + curved surface of conical cavity + area of one flat circular base).
Section E — Key Answers (Case Studies, 4 marks each)
Q36. (i) AB = 4 units; (ii) AC = √13 units; (iii) Centroid = (3, 2).
Q37. (i) Slant height ≈ 6.10 cm; (ii) Volume = 154 cm³; (iii) Total surface area ≈ 144.1 cm².
Q38. (i) P(prize) = 2/7; (ii) P(not prize) = 5/7; (iii) P(both prizes, without replacement) = 9/119.
Step-wise Marking Scheme — General Guidelines
• Section A (MCQ/AR): 1 mark for the correct option only; no partial credit.
• Section B/C/D (VSA/SA/LA): Marks are awarded step-wise — correct method/formula (partial marks even if the final numeric answer is wrong due to a minor computational slip), correct substitution of values, and correct final answer with unit. Alternative correct methods must be given full credit.
• Proof-based questions (e.g. Q29, Q30, Q33): Marks are distributed across statement of the theorem/given-to-prove, construction (if any), logical steps of the proof, and the concluding statement.
• Section E (Case Study): Each sub-part is marked independently as per its allotted marks (1, 1, 2); no negative marking for an incorrect sub-part affecting others.
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