📘 Definition
First Ionization Enthalpy is the minimum amount of energy required to remove the most loosely bound electron from one mole of isolated gaseous atoms in their ground state to form one mole of gaseous unipositive ions.
It is represented by ΔiH₁ and is generally expressed in kJ mol⁻¹.
📘 Explanation
Although ionization enthalpy generally increases from left to right across a period, Nitrogen has a higher first ionization enthalpy than Oxygen. This is an important exception in the second period.
| Element | Atomic Number | Electronic Configuration |
|---|---|---|
| N | 7 | 1s² 2s² 2p³ |
| O | 8 | 1s² 2s² 2p⁴ |
🔹 Nitrogen
Nitrogen has a half-filled 2p³ configuration. Its three 2p orbitals contain one electron each.
A half-filled subshell is relatively stable because of symmetrical distribution and exchange energy. Therefore, more energy is required to remove an electron from nitrogen.
🔹 Oxygen
Oxygen has the configuration 2p⁴. One of the 2p orbitals contains a pair of electrons.
The two electrons in the same orbital experience greater electron-electron repulsion. Therefore, one electron can be removed comparatively easily from oxygen.
Nitrogen has a stable half-filled 2p³ configuration, whereas oxygen has electron-electron repulsion in one paired 2p orbital.
📘 Trend Down a Group
The ionization enthalpy generally decreases as we move down a group in the periodic table.
🔹 Reasons
- Increase in atomic size: A new electron shell is added at each step down the group.
- Increase in shielding effect: The inner electrons shield the valence electron from the attraction of the nucleus.
- Increase in distance: The outermost electron is farther from the nucleus.
- Reduced effective nuclear attraction: The valence electron is held less strongly by the nucleus.
- Therefore, less energy is required to remove the outermost electron.
📊 Example: Group 1
| Element | Trend in Atomic Size | Trend in IE |
|---|---|---|
| Li | Small | High |
| Na | ↑ | ↓ |
| K | ↑ | ↓ |
| Rb | ↑ | ↓ |
| Cs | Large | Low |
📝 20 MCQs with Answers
1. First ionization enthalpy is the energy required to:
✅ Answer
B
2. First ionization enthalpy is generally expressed in:
✅ Answer
C) kJ mol⁻¹
3. The process X(g) → X⁺(g) + e⁻ represents:
✅ Answer
B) First ionization
4. Which has higher first ionization enthalpy?
✅ Answer
A) N
5. Electronic configuration of nitrogen is:
✅ Answer
B
6. Nitrogen has high IE because of its:
✅ Answer
B) Half-filled p-subshell
7. Oxygen has the configuration:
✅ Answer
C) 2p⁴
8. In oxygen, electron-electron repulsion occurs due to:
✅ Answer
B
9. Ionization enthalpy generally decreases:
✅ Answer
B) Down a group
10. Which factor increases down a group?
✅ Answer
A) Atomic size
11. Shielding effect down a group:
✅ Answer
B) Increases
12. Greater atomic size generally causes ionization enthalpy to:
✅ Answer
B) Decrease
13. Which is easier to ionize?
✅ Answer
B
14. The unusual IE trend between N and O is due to:
✅ Answer
A
15. Which subshell is half-filled in nitrogen?
✅ Answer
B) 2p
16. Which element has the lowest IE among Li, Na and K?
✅ Answer
C) K
17. Down a group, the valence electron is:
✅ Answer
B
18. Which generally has higher IE?
✅ Answer
A) Smaller atom
19. Ionization enthalpy is a measure of:
✅ Answer
A
20. Correct statement is:
✅ Answer
B
Q1. Define first ionization enthalpy.
It is the minimum energy required to remove the first electron from one mole of isolated gaseous atoms in their ground state to form one mole of gaseous unipositive ions.
Q2. Why is IE of nitrogen greater than oxygen?
Nitrogen has a stable half-filled 2p³ configuration, whereas oxygen has 2p⁴ configuration with one pair of electrons. Electron-electron repulsion in the paired orbital makes electron removal from oxygen easier.
Q1. Explain why ionization enthalpy decreases down a group.
- Atomic size increases down the group.
- Shielding effect increases due to addition of shells.
- The valence electron is farther from the nucleus.
- Nuclear attraction on the outer electron decreases.
- Hence, less energy is required to remove it.
Q2. Why is nitrogen an exception in the IE trend between N and O?
Nitrogen has the particularly stable half-filled 2p³ configuration. Oxygen has 2p⁴ configuration, in which two electrons occupy the same 2p orbital and experience repulsion. Therefore, oxygen loses an electron more easily than nitrogen.
Q. Explain first ionization enthalpy and discuss its trend down a group.
First ionization enthalpy is the minimum energy required to remove the first electron from one mole of isolated gaseous atoms in their ground state.
Down a group:
- Number of shells increases.
- Atomic radius increases.
- Shielding effect increases.
- Valence electron becomes farther from the nucleus.
- Effective nuclear attraction decreases.
Q. Explain why the first ionization enthalpy of nitrogen is greater than that of oxygen.
The electronic configuration of nitrogen is 1s² 2s² 2p³. The three 2p electrons occupy the three 2p orbitals singly. This is a half-filled configuration, which possesses extra stability.
Oxygen has the configuration 1s² 2s² 2p⁴. One of its 2p orbitals contains a pair of electrons. The electrons in the same orbital experience repulsion.
Therefore, an electron can be removed more easily from oxygen than from nitrogen.
Q1. Define first ionization enthalpy and explain its periodic trend down a group.
Solution
First ionization enthalpy is the minimum energy required to remove the most loosely bound electron from one mole of isolated gaseous atoms in their ground state to form one mole of gaseous unipositive ions.
Trend Down a Group
Ionization enthalpy generally decreases down a group due to the following factors:
- Increase in the number of electron shells.
- Increase in atomic radius.
- Increase in shielding effect.
- Greater distance of the valence electron from the nucleus.
- Decrease in effective nuclear attraction on the valence electron.
- Consequently, less energy is needed to remove the electron.
Q2. Explain why the first ionization enthalpy of nitrogen is greater than that of oxygen.
Solution
| Element | Configuration | Important Feature |
|---|---|---|
| N | 1s² 2s² 2p³ | Stable half-filled 2p subshell |
| O | 1s² 2s² 2p⁴ | Paired-electron repulsion |
Nitrogen has a stable half-filled 2p³ configuration. In oxygen, one 2p orbital contains a pair of electrons. The mutual repulsion between these paired electrons makes removal of one electron easier.
IE₁(N) > IE₁(O)
🎯 Quick Revision
General trend across period: IE ↑
General trend down group: IE ↓
Reason down group: Atomic size ↑ + Shielding ↑
Important exception: IE(N) > IE(O)
Reason: N has stable half-filled 2p³; O has paired-electron repulsion