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Sunday, August 16, 2026

Electrochemistry: Derive the Nernst Equation for a galvanic cell under non-standard conditions

Chapter: Electrochemistry – Nernst Equation

📘 What is the Nernst Equation?

The Nernst equation gives the electrode potential or cell potential of an electrochemical cell under non-standard conditions.

For a galvanic cell, the cell potential depends on the concentration or activity of the reacting species, in addition to the standard cell potential.

Ecell = E°cell − (RT/nF) ln Q

At 298 K:

Ecell = E°cell − (0.0591/n) log Q

🔬 Step 1: Consider a General Galvanic Cell

Consider the cell reaction:

aA + bB → cC + dD

For this reaction, the reaction quotient is:

Q = [C]c[D]d / [A]a[B]b

Pure solids and pure liquids are not included in Q because their activities are taken as unity.

🔬 Step 2: Gibbs Energy and Cell Potential

The Gibbs energy change for an electrochemical reaction is related to the cell potential by:

ΔG = −nFE

Under standard conditions:

ΔG° = −nFE°

Therefore:

ΔG = ΔG° + RT ln Q

🔬 Step 3: Substitute the Electrochemical Relations

We know:

ΔG = −nFE

and

ΔG° = −nFE°

Substituting these into:

ΔG = ΔG° + RT ln Q

we get:

−nFE = −nFE° + RT ln Q

🔬 Step 4: Rearrangement

Divide the entire equation by −nF:

E = E° − (RT/nF) ln Q
This is the Nernst Equation.

🌡️ Step 5: Nernst Equation at 298 K

At 298 K:

R = 8.314 J mol⁻¹ K⁻¹
F = 96485 C mol⁻¹

Changing natural logarithm to common logarithm gives:

E = E° − (0.0591/n) log Q

where n is the number of electrons transferred in the balanced cell reaction.

🔋 Application to a Zn–Cu Galvanic Cell

Consider the Daniell cell:

Zn(s) | Zn²⁺(aq) || Cu²⁺(aq) | Cu(s)

Overall reaction:

Zn + Cu²⁺ → Zn²⁺ + Cu

Here, two electrons are transferred:

n = 2

Therefore:

Q = [Zn²⁺]/[Cu²⁺]

Hence, at 298 K:

Ecell = E°cell − (0.0591/2) log ([Zn²⁺]/[Cu²⁺])

✅ Final Derivation

Starting from:

ΔG = ΔG° + RT ln Q

Using:

ΔG = −nFE      and      ΔG° = −nFE°

we obtain:

Ecell = E°cell − (RT/nF) ln Q

At 298 K:

Ecell = E°cell − (0.0591/n) log Q
E = Cell potential under non-standard conditions
= Standard cell potential
R = Gas constant = 8.314 J mol⁻¹ K⁻¹
T = Absolute temperature in kelvin
n = Number of electrons transferred
F = Faraday constant ≈ 96485 C mol⁻¹
Q = Reaction quotient

Q. Write the Nernst equation for a galvanic cell.

Answer:

Ecell = E°cell − (RT/nF) ln Q

At 298 K:

Ecell = E°cell − (0.0591/n) log Q

Q. Derive the Nernst equation briefly.

  1. For an electrochemical reaction: ΔG = ΔG° + RT ln Q.
  2. Using ΔG = −nFE and ΔG° = −nFE°.
  3. Substitution and rearrangement give: E = E° − (RT/nF) ln Q.

Q. Derive the Nernst equation at 298 K.

ΔG = ΔG° + RT ln Q
−nFE = −nFE° + RT ln Q
E = E° − (RT/nF) ln Q

At 298 K, converting ln to log:

E = E° − (0.0591/n) log Q

Q. Derive the Nernst equation for a galvanic cell and explain the terms involved.

For a general cell reaction:

aA + bB → cC + dD

The reaction quotient is:

Q = [C]c[D]d / [A]a[B]b

Thermodynamically:

ΔG = ΔG° + RT ln Q

For an electrochemical cell:

ΔG = −nFE
ΔG° = −nFE°

Therefore:

E = E° − (RT/nF) ln Q

At 298 K:

E = E° − (0.0591/n) log Q

Q. Derive the Nernst equation for a galvanic cell under non-standard conditions. Explain its significance.

Step 1: Gibbs Energy Relation

ΔG = ΔG° + RT ln Q

Step 2: Relation with Cell Potential

For a galvanic cell:

ΔG = −nFE

Under standard conditions:

ΔG° = −nFE°

Step 3: Substitute

−nFE = −nFE° + RT ln Q

Step 4: Rearrange

E = E° − (RT/nF) ln Q

Step 5: At 298 K

E = E° − (0.0591/n) log Q

Significance

  • It calculates cell potential under non-standard conditions.
  • It shows how ion concentration affects cell potential.
  • It can be used to determine equilibrium conditions.
  • It is useful for calculating the potential of individual electrodes.
Conclusion:

The Nernst equation connects the standard cell potential with the actual cell potential at a specified temperature and composition.

1. The Nernst equation is used to calculate:

A) Cell potential under non-standard conditions
B) Atomic mass
C) Boiling point
D) Density
✅ Answer

A


2. Which equation is correct?

A) E = E° + RT ln Q/nF
B) E = E° − RT ln Q/nF
C) E = E°Q
D) E = E° + Q
✅ Answer

B


3. At 298 K, the Nernst equation contains the factor:

A) 0.0591/n
B) 0.591n
C) 59.1n
D) 9.81/n
✅ Answer

A


4. In the Nernst equation, n represents:

A) Number of ions
B) Number of electrons transferred
C) Number of atoms
D) Number of solutions
✅ Answer

B


5. F in the Nernst equation represents:

A) Force constant
B) Faraday constant
C) Free energy
D) Frequency
✅ Answer

B


6. The approximate value of Faraday constant is:

A) 8.314 C mol⁻¹
B) 96485 C mol⁻¹
C) 22.4 C mol⁻¹
D) 6.022 × 10²³ C mol⁻¹
✅ Answer

B


7. Q in the Nernst equation represents:

A) Heat
B) Reaction quotient
C) Charge only
D) Volume
✅ Answer

B


8. For a reaction aA + bB → cC + dD, Q is:

A) [A][B]/[C][D]
B) [C]ᶜ[D]ᵈ/[A]ᵃ[B]ᵇ
C) [A]ᵃ[B]ᵇ
D) [C][D]
✅ Answer

B


9. Pure solids are generally:

A) Included in Q
B) Not included in Q
C) Always numerator
D) Always denominator
✅ Answer

B


10. The relation between Gibbs energy and cell potential is:

A) ΔG = nFE
B) ΔG = −nFE
C) ΔG = RT
D) ΔG = E/nF
✅ Answer

B


11. Under standard conditions:

A) ΔG° = −nFE°
B) ΔG° = nFE°
C) ΔG° = RT
D) ΔG° = Q
✅ Answer

A


12. A galvanic cell converts:

A) Electrical energy into chemical energy spontaneously
B) Chemical energy into electrical energy
C) Heat into mass
D) Light into chemical energy only
✅ Answer

B


13. If Q = 1, the Nernst equation gives:

A) E = E°
B) E = 0
C) E = 2E°
D) E = Q
✅ Answer

A


14. At equilibrium, the cell potential of a reversible galvanic cell is:

A) Maximum
B) Zero
C) Negative infinity
D) Always 1 V
✅ Answer

B


15. At equilibrium, the reaction quotient is equal to:

A) 0
B) 1
C) K
D) nF
✅ Answer

C) K


16. For the Daniell cell Zn + Cu²⁺ → Zn²⁺ + Cu, n equals:

A) 1
B) 2
C) 3
D) 4
✅ Answer

B) 2


17. For the Daniell cell, Q is:

A) [Cu²⁺]/[Zn²⁺]
B) [Zn²⁺]/[Cu²⁺]
C) [Zn][Cu]
D) [Zn²⁺][Cu²⁺]
✅ Answer

B


18. Increasing the concentration of products generally makes Q:

A) Increase
B) Decrease
C) Zero
D) Always equal to 1
✅ Answer

A


19. The Nernst equation is derived using the relation:

A) ΔG = ΔG° + RT ln Q
B) PV = nRT only
C) E = mc²
D) q = mcΔT
✅ Answer

A


20. The Nernst equation is important because it relates cell potential to:

A) Concentration/activity of reacting species
B) Colour of the solution
C) Atomic radius
D) Melting point only
✅ Answer

A

🎯 Quick Revision

General equation: E = E° − (RT/nF) ln Q
At 298 K: E = E° − (0.0591/n) log Q
ΔG: ΔG = −nFE
Standard ΔG: ΔG° = −nFE°
Q: Reaction quotient
n: Number of electrons transferred
F: Faraday constant