Recoil Momentum of Atoms Emitting Photons
📘 Concept & Complete Theory
When an excited atom changes from a higher energy state to a lower energy state, it emits a photon. Since a photon possesses momentum, the atom receives an equal and opposite recoil momentum.
Excited Hydrogen Atom
H
Photon → p = E/c
Atom Recoil ←
Core Concept:
Initial momentum of atom + system = 0.
After emission:
Atom recoil momentum + photon momentum = 0.
Initial momentum of atom + system = 0.
After emission:
Atom recoil momentum + photon momentum = 0.
Photon Momentum
pγ = Eγ/c
= hν/c
= h/λ
Conservation of Momentum
patom + pphoton = 0
Therefore:
|patom| = |pphoton|
Recoil Velocity
Mv = h/λ
Therefore:
v = h/(Mλ)
Using Photon Energy
v = Eγ/(Mc)
Recoil Kinetic Energy
KR
= p²/(2M)
= Eγ²/(2Mc²)
Hydrogen Atom
Eγ
=
13.6
[1/nf² − 1/ni²]
eV
JEE/NEET Shortcut:
Step 1 → Find transition energy.
Step 2 → Find photon momentum using p = E/c.
Step 3 → Atomic recoil momentum = photon momentum.
Step 4 → Use v = p/M.
Step 1 → Find transition energy.
Step 2 → Find photon momentum using p = E/c.
Step 3 → Atomic recoil momentum = photon momentum.
Step 4 → Use v = p/M.
| Quantity | Formula |
|---|---|
| Photon Energy | E = hν = hc/λ |
| Photon Momentum | p = E/c = h/λ |
| Recoil Momentum | pR = −pγ |
| Recoil Velocity | v = h/(Mλ) |
| Recoil Energy | K = p²/(2M) |
🧮 Fully Solved Example
Question:
A hydrogen atom initially at rest undergoes transition from n = 2 to n = 1. Calculate the recoil velocity.
A hydrogen atom initially at rest undergoes transition from n = 2 to n = 1. Calculate the recoil velocity.
Hydrogen transition energy:
E = 13.6(1 − 1/4)
E = 10.2 eV
E = 10.2 × 1.602×10−19 J
E ≈ 1.634×10−18 J
Photon momentum:
p = E/c
p ≈ 5.45×10−27 kg m/s
For atom:
Mv = p
v = p/M
v ≈ 3.26 m/s
Final Answer ≈ 3.26 m/s opposite to photon.
E = 13.6(1 − 1/4)
E = 10.2 eV
E = 10.2 × 1.602×10−19 J
E ≈ 1.634×10−18 J
Photon momentum:
p = E/c
p ≈ 5.45×10−27 kg m/s
For atom:
Mv = p
v = p/M
v ≈ 3.26 m/s
Final Answer ≈ 3.26 m/s opposite to photon.
🎯 30 JEE / NEET / Competitive MCQs
⚡ 30 Assertion–Reason Questions
🧮 30 Numerical Practice Questions
⭐ 1 Mark Questions — 30
⭐ 2 Marks Questions — 30
⭐ 3 Marks Questions — 30
⭐ 4 Marks Questions — 30
⭐ 5 Marks Questions — 30
⭐ 6 Marks Questions — 30
🚀 Final Revision Formula Sheet
pγ = E/c = hν/c = h/λ
patom = −pγ
v = h/(Mλ)
v = E/(Mc)
KR = E²/(2Mc²)
Eγ =
13.6[1/nf² − 1/ni²] eV
Remember:
Photon → momentum forward
Atom → recoil momentum backward
Total momentum → conserved
Shorter wavelength → larger recoil
Higher photon energy → larger recoil
Heavier atom → smaller recoil
Photon → momentum forward
Atom → recoil momentum backward
Total momentum → conserved
Shorter wavelength → larger recoil
Higher photon energy → larger recoil
Heavier atom → smaller recoil