Class 10 Science – Chapter 2
Reaction of Metals with Salt Solutions
अम्ल, क्षार एवं लवण | Acids, Bases and Salts
1. What is a Displacement Reaction?
A displacement reaction is a chemical reaction in which a more reactive element displaces a less reactive element from its compound.
विस्थापन अभिक्रिया वह रासायनिक अभिक्रिया है जिसमें अधिक क्रियाशील तत्व, कम क्रियाशील तत्व को उसके यौगिक से विस्थापित कर देता है।
General Form / सामान्य रूप
यदि A, B से अधिक क्रियाशील है, तो A, B को उसके यौगिक BC से विस्थापित कर देगा।
Example 1: Zinc and Copper Sulphate
जिंक, कॉपर से अधिक क्रियाशील है। इसलिए Zn, CuSO₄ से Cu को विस्थापित कर देता है।
Example 2: Iron and Copper Sulphate
Iron is more reactive than copper, so iron displaces copper from copper sulphate solution.
Example 3: Copper and Zinc Sulphate
Copper is less reactive than zinc. Therefore, copper cannot displace zinc from zinc sulphate.
A more reactive metal can displace a less reactive metal from its salt solution.
अधिक क्रियाशील धातु, कम क्रियाशील धातु को उसके लवण विलयन से विस्थापित कर सकती है।
2. Why Does Iron Displace Copper from Copper Sulphate?
Iron displaces copper from copper sulphate because iron is more reactive than copper.
लोहा कॉपर सल्फेट से कॉपर को इसलिए विस्थापित करता है क्योंकि लोहा, कॉपर से अधिक क्रियाशील है।
Reaction / अभिक्रिया
Observations / अवलोकन
- Blue colour of CuSO₄ solution gradually changes to green.
- CuSO₄ का नीला रंग धीरे-धीरे हरा हो जाता है।
- Reddish-brown copper is deposited.
- लाल-भूरे रंग का कॉपर जमा होता है।
Why does the colour change?
Copper sulphate solution is blue because of Cu²⁺ ions. During the reaction, Fe²⁺ ions are formed and FeSO₄ solution is pale green.
CuSO₄ विलयन का नीला रंग Cu²⁺ आयनों के कारण होता है। अभिक्रिया के बाद Fe²⁺ आयन बनते हैं और FeSO₄ का विलयन हल्का हरा होता है।
Electronic Explanation
Iron loses electrons and forms Fe²⁺ ions.
Copper ions gain electrons and form metallic copper.
Iron is oxidised while Cu²⁺ is reduced. Therefore, the reaction is also a redox reaction.
3. Reaction Between Zinc and Copper Sulphate
When zinc is placed in copper sulphate solution, zinc displaces copper from copper sulphate because zinc is more reactive than copper.
जब जिंक को कॉपर सल्फेट के विलयन में डाला जाता है, तो जिंक कॉपर को विस्थापित कर देता है क्योंकि जिंक, कॉपर से अधिक क्रियाशील है।
Balanced Chemical Equation
Observation / अवलोकन
- Blue CuSO₄ solution loses its blue colour.
- नीला CuSO₄ विलयन अपना नीला रंग खो देता है।
- Reddish-brown copper gets deposited on zinc.
- जिंक की सतह पर लाल-भूरा कॉपर जमा होता है।
Ionic Equation
Oxidation and Reduction
Zn is oxidised.
Cu²⁺ is reduced.
Zn is the reducing agent and Cu²⁺ acts as the oxidising species. The reaction is displacement as well as redox reaction.
4. Reactivity Series & Applications
Reactivity Series of Metals
The metals are arranged in decreasing order of their reactivity.
धातुओं को उनकी क्रियाशीलता के घटते क्रम में व्यवस्थित किया जाता है।
Important Rules
Examples
Competitive Concept
Suppose metal A displaces metal B from BSO₄ solution. This means A is more reactive than B.
Displacement possible → Reactivity of added metal > Reactivity of metal in salt.
Example
If X displaces Y from YSO₄, then:
If Y cannot displace X from XSO₄:
30 MCQs – Reaction of Metals with Salt Solutions
Answer: B. Displacement
Zn displaces Cu from CuSO₄.
Answer: C. Zn
Zn is more reactive than Cu.
Answer: B. Blue
Cu²⁺ ions impart blue colour to the solution.
Answer: B. ZnSO₄ and Cu
Answer: B. Zn
Answer: A. FeSO₄ + Cu
Answer: B. Pale green
Answer: B. Zn is more reactive
Answer: B. Oxidised
Answer: B. Reduced
Answer: A
Answer: B. Reactivity
Answer: A. Fe
Answer: B. Copper
Answer: B. No reaction
Answer: A
Answer: B. Cu²⁺
Answer: B. Zn
Answer: A
Answer: B
Answer: C. Ag
Answer: C. Zn
Answer: C. Cu + ZnSO₄
Answer: A. Redox reaction
Answer: A. FeSO₄ is formed
Answer: D. Ag
Answer: B
Answer: B. Cu
Answer: B. Zn > Cu
Answer: B
30 Subjective Questions – Complete Solutions
1 Mark Questions
2 Mark Questions
2. Reddish-brown copper is deposited on zinc.
provided A is more reactive than B.
3 Mark Questions
Fe + CuSO₄ → FeSO₄ + Cu
The blue CuSO₄ solution changes towards pale green due to formation of FeSO₄, and copper is deposited.
Zn → Zn²⁺ + 2e⁻
Reduction:
Cu²⁺ + 2e⁻ → Cu
Therefore, Zn is oxidised and Cu²⁺ is reduced.
Fe + CuSO₄ → FeSO₄ + Cu
Mg + CuSO₄ → MgSO₄ + Cu
4 Mark Questions
Equation:
Zn + CuSO₄ → ZnSO₄ + Cu
This proves that Zn is more reactive than Cu.
Cu + ZnSO₄ → No reaction — Cu is less reactive than Zn.
Fe + CuSO₄ → FeSO₄ + Cu
Zn → Zn²⁺ + 2e⁻
Cu²⁺ gains two electrons:
Cu²⁺ + 2e⁻ → Cu
Thus Zn undergoes oxidation and Cu²⁺ undergoes reduction.
(i) Cu + ZnSO₄
(ii) Zn + FeSO₄
(iii) Fe + CuSO₄
(ii) Reaction occurs — Zn is more reactive than Fe.
(iii) Reaction occurs — Fe is more reactive than Cu.
5 Mark Questions
General:
A + BC → AC + B
Examples:
Zn + CuSO₄ → ZnSO₄ + Cu
Fe + CuSO₄ → FeSO₄ + Cu
Mg + CuSO₄ → MgSO₄ + Cu
These reactions are possible because the added metals are more reactive than copper.
Molecular equation:
Zn + CuSO₄ → ZnSO₄ + Cu
Ionic equation:
Zn + Cu²⁺ → Zn²⁺ + Cu
Oxidation:
Zn → Zn²⁺ + 2e⁻
Reduction:
Cu²⁺ + 2e⁻ → Cu
Copper appears as a reddish-brown deposit.
K > Na > Ca > Mg > Al > Zn > Fe > Pb > H > Cu > Hg > Ag > Au
A metal higher in the series displaces a metal lower in the series from its salt solution.
For example:
Zn > Cu
Therefore:
Zn + CuSO₄ → ZnSO₄ + Cu
But:
Cu + ZnSO₄ → No reaction.
Equation:
Fe + CuSO₄ → FeSO₄ + Cu
Observations:
1. Blue colour of CuSO₄ changes towards pale green.
2. Reddish-brown copper is deposited.
3. Iron slowly dissolves.
Reason: Fe lies above Cu in the reactivity series.
Example:
Zn + CuSO₄ → ZnSO₄ + Cu
Double displacement: Two compounds exchange their ions.
Example:
AgNO₃ + NaCl → AgCl + NaNO₃
6 Mark Questions
Molecular equation:
Zn + CuSO₄ → ZnSO₄ + Cu
Ionic equation:
Zn + Cu²⁺ → Zn²⁺ + Cu
Oxidation:
Zn → Zn²⁺ + 2e⁻
Reduction:
Cu²⁺ + 2e⁻ → Cu
Zinc loses electrons and is oxidised. Copper ions gain electrons and are reduced. Therefore, the reaction is both displacement and redox.
The blue colour gradually fades and reddish-brown copper deposits on zinc.
Equation:
Zn + CuSO₄ → ZnSO₄ + Cu
This shows that Zn has displaced Cu. Hence Zn is more reactive than Cu.
(a) Zn + CuSO₄
(b) Cu + ZnSO₄
(c) Fe + CuSO₄
Reason: Zn is more reactive than Cu.
(b) Cu + ZnSO₄ → No reaction
Reason: Cu is less reactive than Zn.
(c) Fe + CuSO₄ → FeSO₄ + Cu
Reason: Fe is more reactive than Cu.
If metal A is above metal B:
A > B
then:
A + B-salt → A-salt + B
Example:
Zn > Cu
Therefore:
Zn + CuSO₄ → ZnSO₄ + Cu
If A is below B, displacement does not occur.
1. They demonstrate relative reactivity of metals.
2. They help establish the reactivity series.
3. They explain extraction and recovery of some metals.
4. They demonstrate oxidation-reduction processes.
5. They help predict whether a reaction will occur.
6. They provide experimental evidence for electron transfer.
Example:
Zn + CuSO₄ → ZnSO₄ + Cu
This single reaction demonstrates displacement, oxidation, reduction and relative reactivity.
Reaction of Metals with Salt Solutions
Concept + Reactions + MCQs + Subjective Questions