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Thursday, April 9, 2026

Dual Nature of Matter and Radiation - Important Formulas Table

 Dual Nature of Matter and Radiation - Important Formulas Table

S.No.Concept / QuantityFormulaKey Notes
1Energy of PhotonE=hν=hcλ E = h\nu = \frac{hc}{\lambda} Planck’s relation
2Momentum of Photonp=hλ=Ec p = \frac{h}{\lambda} = \frac{E}{c} -
3Einstein’s Photoelectric Equationhν=ϕ0+Kmax h\nu = \phi_0 + K_{\max} -
4Maximum Kinetic EnergyKmax=hνϕ0=eV0 K_{\max} = h\nu - \phi_0 = eV_0 Stopping potential
5Work Functionϕ0=hν0 \phi_0 = h\nu_0 -
6Threshold Frequencyν0=ϕ0h \nu_0 = \frac{\phi_0}{h} -
7Threshold Wavelengthλ0=hcϕ0 \lambda_0 = \frac{hc}{\phi_0} -
8de Broglie Wavelengthλ=hp=hmv \lambda = \frac{h}{p} = \frac{h}{mv} Matter wave
9de Broglie Wavelength (Accelerated Electron)λ=h2meV \lambda = \frac{h}{\sqrt{2meV}} V in volts
10de Broglie Wavelength (in terms of KE)λ=h2mK \lambda = \frac{h}{\sqrt{2mK}} -
11Heisenberg Uncertainty Principle (Position-Momentum)ΔxΔph4π \Delta x \cdot \Delta p \geq \frac{h}{4\pi} -
12Heisenberg Uncertainty Principle (Energy-Time)ΔEΔth4π \Delta E \cdot \Delta t \geq \frac{h}{4\pi} -
13Number of Photons per secondn=Phν n = \frac{P}{h\nu} P = power
14Intensity of LightI=nhνA I = \frac{nh\nu}{A} -
15Slope of Kmax K_{\max} vs ν \nu graphSlope = h (Planck’s constant)-
16Cut-off PotentialV0=hνϕ0e V_0 = \frac{h\nu - \phi_0}{e} -
17de Broglie Wavelength for Charged Particleλ=h2mqV \lambda = \frac{h}{\sqrt{2mqV}} q = charge
18Ratio of de Broglie wavelengths (e⁻ & p) at same speedλeλp=mpme \frac{\lambda_e}{\lambda_p} = \sqrt{\frac{m_p}{m_e}} -
19Compton ShiftΔλ=hm0c(1cosθ) \Delta\lambda = \frac{h}{m_0c}(1 - \cos\theta) Compton wavelength hm0c \frac{h}{m_0c}
20Rest Mass EnergyE0=mc2 E_0 = mc^2 Einstein mass-energy
21Maximum wavelength for photoelectric effectλmax=λ0 \lambda_{\max} = \lambda_0 -
22Velocity of Electron from de Brogliev=hmλ v = \frac{h}{m\lambda} -
23Kinetic Energy from de BroglieK=h22mλ2 K = \frac{h^2}{2m\lambda^2} -
24Photon Momentum in eV/cp=Ec=hλ p = \frac{E}{c} = \frac{h}{\lambda} Useful unit
25hc in eV-Åhc=12400 hc = 12400 eV ÅVery important constant
26Minimum Uncertainty in VelocityΔvh4πmΔx \Delta v \geq \frac{h}{4\pi m \Delta x} -
27Davisson-Germer Relation2dsinθ=nλ 2d \sin\theta = n\lambda Electron diffraction
28Bragg’s Law for Electron Wavesnλ=2dsinθ n\lambda = 2d \sin\theta -
29Photoelectric CurrentI I \propto Intensity (above threshold)Saturation current
30de Broglie Wavelength of Thermal Neutronλ=h3mkT \lambda = \frac{h}{\sqrt{3m kT}} -
31Group Velocity of Matter Wavevg=dωdk=v v_g = \frac{d\omega}{dk} = v (particle velocity)-
32Phase Velocity of Matter Wavevp=ωk=c2v v_p = \frac{\omega}{k} = \frac{c^2}{v} > c
33Number of Photons in Energy EN=Ehν N = \frac{E}{h\nu} -
34Radiation Pressure (Absorption)P=Ic P = \frac{I}{c} -
35Radiation Pressure (Reflection)P=2Ic P = \frac{2I}{c} -
36Momentum Transferred by Photon (Absorption)Δp=hλ \Delta p = \frac{h}{\lambda} -
37Momentum Transferred by Photon (Reflection)Δp=2hλ \Delta p = \frac{2h}{\lambda} -
38de Broglie Frequencyν=Eh \nu = \frac{E}{h} -
39Wave Number of Photonνˉ=1λ \bar{\nu} = \frac{1}{\lambda} -
40Stopping Potential for Two Frequenciese(V1V2)=h(ν1ν2) e(V_1 - V_2) = h(\nu_1 - \nu_2) -
41Maximum KE in different metalsKmax1Kmax2=ϕ2ϕ1 K_{\max1} - K_{\max2} = \phi_2 - \phi_1 -
42de Broglie Wavelength of Electron in Bohr Orbit2πr=nλ 2\pi r = n\lambda -
43Minimum Energy of Photon for EmissionEmin=hν0 E_{\min} = h\nu_0 -
44Relation between λ and V (Electron)λ(in A˚)=12.27V \lambda (\text{in Å}) = \frac{12.27}{\sqrt{V}} Practical formula
45Relation between λ and V (Proton)λ(in A˚)=0.286V \lambda (\text{in Å}) = \frac{0.286}{\sqrt{V}} -
46Planck’s Constant from Graphh= h = slope of Kmax K_{\max} vs ν \nu -
47Work Function from Graphϕ0=hν0 \phi_0 = h\nu_0 (x-intercept)-
48Uncertainty in Position for ElectronΔxh4πmΔv \Delta x \geq \frac{h}{4\pi m \Delta v} -
49Compton Wavelength of Electronλc=hmec=0.0243 \lambda_c = \frac{h}{m_e c} = 0.0243 Å-
50de Broglie Wavelength Ratio (Same KE)λ1λ2=m2m1 \frac{\lambda_1}{\lambda_2} = \sqrt{\frac{m_2}{m_1}} -

Important Constants

  • h=6.626×1034 h = 6.626 \times 10^{-34} J s
  • hc=12400 hc = 12400 eV Å
  • h4π=5.27×1035 \frac{h}{4\pi} = 5.27 \times 10^{-35} J s
  • Electron mass me=9.1×1031 m_e = 9.1 \times 10^{-31} kg
  • c=3×108 c = 3 \times 10^8 m/s

Note: This comprehensive table covers almost all formulas needed for Class 12 Board Exams, JEE Main, JEE Advanced, and NEET.

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